Can someone please explain the bonus system for USApocalypse
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Can someone please explain the bonus system for USApocalypse
I don't quite understand the Radiation Nexus thingie...
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ClessAlvein
- Posts: 151
- Joined: Sun Mar 04, 2007 9:30 pm
If you hold 1 or 2 territories marked with the radiation symbol, then you get a penalty of -1. If you hold 3 such territories, you get neither a bonus nor a penalty (although the passive +1 from holding 3 territories still applies unless you're under 12 territories). If you hold 4 radiated territories or more, you get bigger and bigger bonuses. If you hold all 6, you get a whopping +9 bonus. This isn't easy to get, though, because you'd have a foot in literally every continental bonus, so the other players aren't going to be very happy about it.
i refer anyone interested in defending their explanation to Game 917541.
My opponent holds all six radiation symbols, yet does not get nine bonus armies.
2007-10-02 04:28:42 - King Conqueror receives -5 armies for holding irradiated territory
2007-10-02 04:28:42 - King Conqueror receives 10 armies for holding a radiation nexus
What gives? How does this relate to the on-map legend?
My opponent holds all six radiation symbols, yet does not get nine bonus armies.
2007-10-02 04:28:42 - King Conqueror receives -5 armies for holding irradiated territory
2007-10-02 04:28:42 - King Conqueror receives 10 armies for holding a radiation nexus
What gives? How does this relate to the on-map legend?
- BaldAdonis
- Posts: 2334
- Joined: Fri Aug 24, 2007 1:57 am
- Location: Trapped in Pleasantville with Toby McGuire
Your (xi) should just be an i, because that's what increments. The x has no value; I think that's what philh's point was.MeDeFe wrote:It's a normal sigma function, I just don't know how to get the i so it's "lower down", like when you have functions to the power of two or more and end up having multiple possible values for x and enumerate them with an index.
No need to sum anyways, there's a nicer closed form, just simplifying what philh had. (n choose 2) - n = n(n-1)/2 - n = n(n-3)/2