It all begins on Scotts next turn if you would like to follow along.
21 cards, 7 cash-in test - [Complete]
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- sully800
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Well, we have all the cards that we need- the right numbers and the right colors. Everyone looks to be in a good position for the action to work. Let's just hope there are no miracle dice and we don't see 20 defeat 45 or something like that!
It all begins on Scotts next turn if you would like to follow along.
It all begins on Scotts next turn if you would like to follow along.
- maniacmath17
- Posts: 640
- Joined: Sat May 06, 2006 8:32 pm
there really isn't any way that the dice can prevent this from happening. Even if someone loses like a 45 v 20 or something, we can simply let the player time out, fort some more troops to him and try again next round.
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chessplaya
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AK_iceman wrote:Nah, I'm looking to have 21 cards in my hand at the same time. And then cashing them all in a row.
the max cards u can hold without having to cash is 9....so what r u trying to figure out ?
Edit:
then when he holds the 9 cards he lets the time ran off...and the next player eliminates him and lets the time ran off thats 13 cards ....etc. etc.
this actually would work....amazing!!! good luck guys
Veni...
Vidi...
Vici...
Vidi...
Vici...
- maniacmath17
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- sully800
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It wouldn't really have mattered since in theory no one would have cashed up to this point. Keep in mind that the person who is collecting the cards never gets to cash until we've reached our goal....maniac can cash because he is the bystander and not involved in the actual process. Scott misunderstood us one round and attacked so he had too many cards and had to cash.RobinJ wrote:Would this not have been a whole lot easier if you had made it escalating cards?
I originally thought we would make it escalating to get the sets high in the beginning and have some enormous cash in at the end. Having high sets could have made balancing the armies easier but it would have just taken longer.
- JupitersKing
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- Optimus Prime
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- SirSebstar
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- sully800
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In a team game, if you deadbeat your partner inherits your cards (fairly new rule).SirSebstar wrote:that be freestyle. sweet.AK_iceman wrote:Good job guys, thanks for helping me out.![]()
Stay tuned for the 24 cards, 8 cash-in test - Take 1 experiment.![]()
but eh how,
5 and 4,4,4, and your 4 = 21, how to go to 23 before the need to cash in?
Otherwise 25 is possible, but eh how 23??
So you have
1- 5
2- 5
3- 4
4- 5
5- 5
6- anything
1 and 4 deadbeat which gives player 2 ten cards and player 5 ten cards.
Then player 3 takes both of them out and has 24 total.
- DiM
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24 cards don't guarantee 8 sets. what will you do if player 3 ends up with just 7 sets? will you repeat the experiment? 
“In the beginning God said, the four-dimensional divergence of an antisymmetric, second rank tensor equals zero, and there was light, and it was good. And on the seventh day he rested.”- Michio Kaku
- DiM
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well if you guys are really unlucky you could end up cashing dozens of sets before the right combination comes along and when it does crappy dice spoil the atackssully800 wrote:It doesn't guarantee it, but its possible. That's why you name what cards you have and if it doesn't yield the right number of sets, someone cashes.DiM wrote:24 cards don't guarantee 8 sets. what will you do if player 3 ends up with just 7 sets? will you repeat the experiment?
“In the beginning God said, the four-dimensional divergence of an antisymmetric, second rank tensor equals zero, and there was light, and it was good. And on the seventh day he rested.”- Michio Kaku
That scenario wouldn't exactly work in that order. Once player 1 deadbeated then player 2 would have to cash before he'd be able to play again. What we would need to do is have player 4 deadbeat first which would give player 5 10 cards. Then Player 2 eliminates player 5 and that gives him 14 cards. then player 1 and 3 deadbeat giving player 2 a total of 24 cards and 8 cash ins.sully800 wrote:In a team game, if you deadbeat your partner inherits your cards (fairly new rule).
So you have
1- 5
2- 5
3- 4
4- 5
5- 5
6- anything
1 and 4 deadbeat which gives player 2 ten cards and player 5 ten cards.
Then player 3 takes both of them out and has 24 total.
- maniacmath17
- Posts: 640
- Joined: Sat May 06, 2006 8:32 pm
yeah AK's right on this one, can't have someone kill 2 people since after killing 1 person that player would be forced to cash before making any more attacks.
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