is 20 v 1 and not take it,random dice?
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is 20 v 1 and not take it,random dice?
Is 20 v 1 & not take it random dice?
Re: is 20 v 1 and not take it,random dice?
Lord......I thought 21 against 5 and not taking it was bad. Mind you i've just had 14 against 12 and advanced 11 in so it does swing in roundabouts. Chin up old son.Tarrus wrote:Is 20 v 1 & not take it random dice?
- lord voldemort
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- BENJIKAT IS DEAD
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12v1 - I assume you mean 11 attacking armies? - lose 0.0015% of the time.
So this is once every 66 thousand times this attack is attempted.
I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.
The important thing to remember is that "random" does not equal "average".
So this is once every 66 thousand times this attack is attempted.
I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.
The important thing to remember is that "random" does not equal "average".

- KoE_Sirius
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- BENJIKAT IS DEAD
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BENJIKAT IS DEAD wrote:12v1 - I assume you mean 11 attacking armies? - lose 0.0015% of the time.
So this is once every 66 thousand times this attack is attempted.
I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.
The important thing to remember is that "random" does not equal "average".
oops I read 12 instead of 20
That's a much much smaller number...

- DiM
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but still possible. even if much smaller.BENJIKAT IS DEAD wrote:BENJIKAT IS DEAD wrote:12v1 - I assume you mean 11 attacking armies? - lose 0.0015% of the time.
So this is once every 66 thousand times this attack is attempted.
I guess this attack happens many thousands of times a day on CC, so it's actually not that unlikely to occur once or twice around the place.
The important thing to remember is that "random" does not equal "average".
oops I read 12 instead of 20![]()
That's a much much smaller number...
“In the beginning God said, the four-dimensional divergence of an antisymmetric, second rank tensor equals zero, and there was light, and it was good. And on the seventh day he rested.”- Michio Kaku
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the doorman
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??
20 v 1 though!!!
lol,funny now,but at the time i could have cried i can tell ya ll
lol,funny now,but at the time i could have cried i can tell ya ll
It can be brutal. I think there should be some sort of 'overwhelming strength' bonus or something. I mean, how many times outside of Hollywood does one guy take down 20?
Maybe if you have > 5 times the armies of the defending territory, you get to roll 4 dice, or get +1 to your highest roll, or something. Many of the real-world risk variants include such bonuses, usually if you have a 'commander' in the attacking territory, or something. An OVERWHELMING difference in the size of one side could grant the same advantage. It can be extremely frustrating to outplay your opponent, only to lose to dice results so far outside the standard deviation as to be mind-boggling.
My €.02
-snoop
Maybe if you have > 5 times the armies of the defending territory, you get to roll 4 dice, or get +1 to your highest roll, or something. Many of the real-world risk variants include such bonuses, usually if you have a 'commander' in the attacking territory, or something. An OVERWHELMING difference in the size of one side could grant the same advantage. It can be extremely frustrating to outplay your opponent, only to lose to dice results so far outside the standard deviation as to be mind-boggling.
My €.02
-snoop
