Conquer Club

When there is a 3 vs 2 dice situation (the most common roll), which are the odds for:

1) attacker losing 2 dice
2) attacker losing 1 dice and the defender losing one dice
3) defender losing 2 dice.

I'm interested more in statistical calculations, rather than strange fairytales.

Thank you all in advance.

AshleyAnderson wrote:When there is a 3 vs 2 dice situation (the most common roll), which are the odds for:

1) attacker losing 2 dice
2) attacker losing 1 dice and the defender losing one dice
3) defender losing 2 dice.

I'm interested more in statistical calculations, rather than strange fairytales.

Thank you all in advance.

3 v 2:
Total Permutations: 7776
Defender loses 2 units: 1217 (16%)
Each lose 1 unit: 2331 (30%)
Attacker loses 2 units: 4228 (54%)

This site might help you:
http://www.cs.man.ac.uk/~iain/riskstats.php

This website only operates in a strange fairy tale manner.

All the statistics you learned in university do not apply to conquer club.

YukFoo wrote:This website only operates in a strange fairy tale manner.

All the statistics you learned in university do not apply to conquer club.

Except that it's been well documented the dice aren't random because they stick too close to the statistical odds.

YukFoo wrote:This website only operates in a strange fairy tale manner.

Well it's perfect for this new imaginary member.

And the stats posted are wrong - they account for the fact that back in the day in Risk, you can choose how many dice you roll as defender (at least, I think they are correct for that scenario). If an attackers rolls 666, just roll 1 die. If he rolls 334, roll 2.

Actual odds amount to ~37%, ~34% and ~29% for 2-0, 1-1 and 0-2 respectively.